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A stone of mass 0.05 kg is thrown vertic...

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

A

9.8 N vertically downwards

B

0.98N vertically downwards

C

0.49N vertically downwards

D

0.49N vertically downwards

Text Solution

Verified by Experts

The correct Answer is:
C

`vec(F)_(g)= +m vec(g)= 0.05 xx (-9.8 hat(j)) = -0.49 hat(j)= 0.49N` vertically downwards
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