Three resistances `2 Omega , 3 Omega and 4 Omega ` are connected in parallel . The ratio of currents passing through them when a potential differences is applied across its ends will be

Options

A. `4: 3: 2`
B. `5: 4: 3`
C. `6: 4: 3`
D. `6: 3: 2`

Answer

C

Explanation

When resistors are connected in parallel `I alpha (1)/(R )`
`rArr I_(1): I_(2) : I_(3)= (1)/(2): (1)/(3): (1)/(4) rArr I_(1): I_(2): I_(3) = 6: 4: 3`