A parallel plate capacitor is charged and then isolated . The effect if increasing the plate separation on charge , potential and capacitance respectively are

Options

A. constant, increase, decrease
B. constant, decrease, increase
C. increases, decreases, decreases
D. constant, decreases, decreases

Answer

A

Explanation

Since capacitor is isolated charge Q= Constant

Potential difference `V= EL = (sigma)/(epsi_(0)) L`
Since Lincreases, Vincreases capacitance `C= (epsi_(0)A)/(L)` as L increases C decreases
Caution: The plate separation cannot be increased indefinitely otherwise `vec(E )= (sigma)/(epsi_(0)) hat(n)` can.t be maintainced within the capacitor plates