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A proton beam enters a magnetic field of...

A proton beam enters a magnetic field of `10^(-4) " Wb " m^(-2)` Wb normally. If the specific charge of the proton is `10^(11) " C " kg^(-1)` and its velocity is `10^(9) " m "s^(-1)` then the radius of the circle described will be

A

1m

B

100m

C

10m

D

0.1m

Text Solution

Verified by Experts

The correct Answer is:
B

`r= (mv)/(qB) rArr r= (10^(9))/(10^(11) xx 10^(-4))= 10^(2)m = 100m`
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