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In Wheatstone's network P = 2 Omega , Q ...

In Wheatstone's network P =` 2 Omega , Q = 2 Omega , R = 2 Omega and S = 3 Omega` The resistance with which S is to shunted in order that the bridge may be balanced is

A

`6Omega`

B

`4Omega`

C

`2Omega`

D

`1Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`(P)/(Q)= (R )/(S^(1))`
`(2)/(2) = (2)/((3 xx x)/(3 + x)) rArr (3x)/(3+ x)=2 rArr 3x = 6+ 2x rArr x= 6 Omega`
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