Light of wavelength 600nm is incident normally on a slit of width 0.2 mm. The anuglular width of central maxima in the diffraction pattern is (measured from miminum to minimum )

Options

A. `6xx10^(-3)` rad
B. `4xx10^(-3)` rad
C. `2.4xx10^(-3)` rad
D. `4.5xx10^(-3)` rad

Answer

A

Explanation

Linear width of central maxima is = `(2lambdaD)/(a)`
Angular width of central maxima is = `=((2lambdaD)/(a))/(D)`
`=(2lambda)/(a)`
`=(2xx6xx10^(-7))/(2xx10^(-4))`
`=6xx10^(-3)` rad