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A radio - active sample of half- life 10...

A radio - active sample of half- life 10 days contains 1000 x nuclei . Number of original nuclie present after 5 days is

A

707x

B

750x

C

500x

D

250x

Text Solution

Verified by Experts

The correct Answer is:
A

`N=(N_(0))/(2^(n))`
Here `n=(1)/(2)` and `N_(0)=1000x`
`therefore N=(1000x)/(2^((1)/(2)))=(1000x)/(sqrt(2))=0.707xx1000x`
`N=707x`
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