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1.0 g of Mg is burnt with 0.28 g of O(2)...

1.0 g of Mg is burnt with 0.28 g of `O_(2)` in a closed vessel. Which reactant is left in excess and how much ?

A

Mg, 5.8 g

B

Mg, 0.58 g

C

`O_(2)`, 0.24g

D

`O_(2)`, 2.4g

Text Solution

Verified by Experts

The correct Answer is:
B
`2Mg+O_(2) to 2MgO`
48g of Mg requires 32 g of `O_(2)`
? requires 0.28 g of `O_(2)`
Mass of magnesium required `=(48xx0.28)/(32)=0.42g`
But 1 g of Mg is available. Thus, Mg is the excess reagent.
Excess of Mg left behind `=1-0.42=0.58g`
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