One of the following conversion results in the change of hybridization and gemetry :

Options

A. `H_2O " to " H_3O^(+)`
B. `BF_3 " to " BF_4^(-)`
C. `NH_3 " to "N^(+)H_4`
D. `CH_4" to " C_2H_6`

Answer

B

Explanation

In the conversion of `BF_3 " to " BF_4^(-)`
`:." In " BF_3` hybridisation is `Sp^2` while in `BF_4^(-)` the hybridisation is `sp^3`.