In `H_2-O_2` fuel cell the reaction occurring at cathode is

Options

A. `H_((aq))^(+) + OH_((aq)) to H_2O_((l))`
B. `H + e^(-) to 1//2 H_2`
C. `O_(2(g)) + 2H_2O_((l)) + 4e^(-) to 4OH_((aq))`
D. `2H_(2(l)) + O_(2(g)) to 2H_2O_((l))`

Answer

C

Explanation

At anode , `2H_2(g) + 4OH^(-) (aq) to 4H_2O (l) +2e^(-)`
At cathode : `O_2(g) + 2H_2O (l) + 4e^(-) to 4OH^(-) (aq)`
Overall reaction : `2H_2(g) + O_2(g) to 2H_2O (l)`