The hydrolysis of optically active 2- bromobutane with aqueous NaOH result in the formation of

Options

A. `(pm)` butan - 2- ol
B. `(pm)` butan - 1- ol
C. (-) butan - 2- ol
D. (+) butan - 2- ol

Answer

A

Explanation

Usually `1^@` carbocation followes second order kinetics and `2^@and 3^@` carbocation follows first order kinetics.
The reaction between 2- tromobutonewith equal NaOH follows first order kinetic, i.e.,the rate of reaction depends upon the concentration of 2-brombutane (`S_N 1` mechanism).

Since, the 2-bromobutane is optically active than the produt is a receive mixture. This is because carbocations are as intermadiate in `S_N1` reactions. Since, carbonation being `Sp^2`-hybridized is planar species, the attack of the nucleotide on it can occur from both the face with almost case giving a 50 : 50 mixture of two enantiomes.