How many coulombs of electricity are required for the oxidation of one mol of water to dioxygen ?

Options

A. `19.3 xx 10^3 C`
B. `1.93 xx 10^5C`
C. `1.93 xx 10^4C`
D. `9.65 xx 10^4C`

Answer

B

Explanation

`H_2O to 2H^(+) + 1/2 O_2 + 2e^(-) " " (2e^(-) = 2f)`
Hence coulombs of electricity required for the oxidation of one mole of water dioxygen `=2 xx 96500 = 193000C = 1.9 xx 10^5C`.