Home
Class 12
PHYSICS
If displacement x= t^(4) , then the rati...

If displacement `x= t^(4)` , then the ratio of acceleration and velocity of motion will be

A

`(3)/(t)`

B

`(t)/(3)`

C

3t

D

`(4)/(t)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of acceleration to velocity given the displacement equation \( x = t^4 \). ### Step 1: Find the velocity The velocity \( v \) is defined as the rate of change of displacement with respect to time. We can find the velocity by differentiating the displacement \( x \) with respect to time \( t \). \[ v = \frac{dx}{dt} \] Given \( x = t^4 \), we differentiate: \[ v = \frac{d(t^4)}{dt} = 4t^3 \] ### Step 2: Find the acceleration The acceleration \( a \) is defined as the rate of change of velocity with respect to time. We can find the acceleration by differentiating the velocity \( v \) with respect to time \( t \). \[ a = \frac{dv}{dt} \] Now, we differentiate \( v = 4t^3 \): \[ a = \frac{d(4t^3)}{dt} = 12t^2 \] ### Step 3: Find the ratio of acceleration to velocity Now that we have both the acceleration and velocity, we can find the ratio \( \frac{a}{v} \): \[ \frac{a}{v} = \frac{12t^2}{4t^3} \] ### Step 4: Simplify the ratio We can simplify the ratio: \[ \frac{a}{v} = \frac{12}{4} \cdot \frac{t^2}{t^3} = 3 \cdot \frac{1}{t} = \frac{3}{t} \] ### Final Answer The ratio of acceleration to velocity is: \[ \frac{a}{v} = \frac{3}{t} \]

To solve the problem, we need to find the ratio of acceleration to velocity given the displacement equation \( x = t^4 \). ### Step 1: Find the velocity The velocity \( v \) is defined as the rate of change of displacement with respect to time. We can find the velocity by differentiating the displacement \( x \) with respect to time \( t \). \[ v = \frac{dx}{dt} \] ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    MTG-WBJEE|Exercise WB JEE WORKOUT ( CATEGORY 2 : Single Option Correct Type (2 Marks))|15 Videos
  • KINEMATICS

    MTG-WBJEE|Exercise WB JEE WORKOUT ( CATEGORY 3 : One or More than One Option Correct Type (2 Marks))|10 Videos
  • HEAT AND THERMAL PHYSICS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS|15 Videos
  • KINETIC THEORY OF GASES

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (MCQ)|7 Videos

Similar Questions

Explore conceptually related problems

If displacement x at time t is x=sqrt(1+t^(2)) , then acceleration is

The position function x= (6.0m) cos [(3pi "rad"//s) t+ pi//3" rad"] gives the simple harmonic motion of a body. At t=21s, what are the (a) displacement, (b) velocity, (c ) acceleration, and (d) phase of the motion? Also, what are the (e ) frequency and (f) period of the motion?

Knowledge Check

  • Displacement x = t^(3) - 12t + 10 . The acceleration of particle when velocity is zero is given by

    A
    12 units
    B
    10 units
    C
    2 units
    D
    1 units
  • Displacement x=t^(3)-12t+10 . The acceleration of particle when velocity is zero is given by

    A
    12 units
    B
    10 units
    C
    2 units
    D
    1 units
  • If displacement x at time t is x = sqrt(1+ t^(2)) , then acceleration is

    A
    `(1)/(x)`
    B
    `(1)/(x^(2))`
    C
    `(1)/(x^(3)`
    D
    `x^(3)`
  • Similar Questions

    Explore conceptually related problems

    If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the acceleration of particle at t=2 is

    Assertion : For a given simple harmonic motion displacement (from the mean position) and acceleration have a constant ratio. Reason : T = 2pi sqrt(|("displacement")/("acceleration")|) .

    For motion of an object along the x-axis the velocity v dipends on the displacement x an v=3x^(2) , then what is the acceleration at x=2 m .

    Distance is a scalar quantity. Displacement is a vector quqntity. The magnitude of displacement is always less than or equal to distance. For a moving body displacement can be zero but distance cannot be zero. Same concept is applicable regarding velocity and speed. Acceleration is the rate of change of velocity. If acceleration is constant, then equations of kinematics are applicable for one dimensional motion under the gravity in which air resistance is considered, then the value of acceleration depends on the density of medium. Each motion is measured with respect of frame of reference. Relative velocity may be greater // smaller to the individual velocities. A particle is moving along the path y=4x^(2) . The distance and displacement from x=1 to x=2 is (nearly) :-

    If x denotes displacement in time t and x=a cost, then acceleration is :-