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A graph of acceleration versus time of a...

A graph of acceleration versus time of a particle starting from rest at t =0 is shown. The speed of the particle at t=14 second is

A

`2 ms^(-1)`

B

`34 ms^(-1)`

C

`20 ms^(-1)`

D

`42 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Arca enclosed betwecn acceleration-time curve and the time axis represents velocity of the particle.
`v= (1)/(2) (12+6)4 -(1)/(2)xx2xx2=36-2 = 34 ms^(-1)`
Since initial velocity is zero and the gain in velocity is `34 ms^(1)`. Therefore, the velocity at 14 second is 34 `ms^(-1).`
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