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Two boys are standing at the ends A and ...

Two boys are standing at the ends A and B of a ground where AB= a. The boy at B starts running in a direction perpendicular to AB with velocity v. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

A

`(a)/(sqrt(nu^(2)+nu_(1)^(2)))`

B

`(a)/(nu+nu_(1))`

C

`(a)/(nu-nu_(1))`

D

`sqrt(a^(2)/(nu^(2)-nu_(1)^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
D

`t=(a)/(nu)=(a)/(sqrt(nu^(2)-nu_(1)^(2)))`
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