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If |vecAxxvecB|=sqrt(3) vecA.vecB, then ...

If `|vecAxxvecB|=sqrt(3) vecA.vecB`, then the value of `|vecA+vecB|` is

A

`(A^(2)+B^(2)+AB)^(1//2)`

B

`(A^(2)+B^(2)+(AB)/(sqrt(3)))^(1//2)`

C

A+B

D

`(A^(2)+B^(2)+sqrt(3)AB)^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`|vecAxxvecB|=sqrt(3)vecA.vecB`
`|A||B|sin theta=sqrt(3)|A||B|costheta`
`tan theta = sqrt(3) implies theta= 60^(@)`
`|vecA+vecB|=sqrt(|A|^(2)+|B|^(2)+2|A||B|"cos"theta)`
`= (A^(2)+B^(2)+AB)^(1//2)`
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