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A spherical ball contracts in radius by ...

A spherical ball contracts in radius by 2%, when subjected to a normal uniform force. The volumetric strain produced in ball is

A

`6* 10^-2`

B

`2*10^-2`

C

`4*10^-2`

D

`10^-2`

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The correct Answer is:
To find the volumetric strain produced in a spherical ball that contracts in radius by 2%, we can follow these steps: ### Step 1: Define the Initial Radius Let the initial radius of the spherical ball be denoted as \( R \). ### Step 2: Calculate the Final Radius Since the radius contracts by 2%, the final radius \( r \) can be calculated as: \[ r = R - 0.02R = 0.98R \] ### Step 3: Calculate the Initial Volume The initial volume \( V_i \) of the spherical ball can be calculated using the formula for the volume of a sphere: \[ V_i = \frac{4}{3} \pi R^3 \] ### Step 4: Calculate the Final Volume The final volume \( V_f \) of the spherical ball after contraction can be calculated using the final radius: \[ V_f = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (0.98R)^3 \] Calculating \( (0.98R)^3 \): \[ (0.98R)^3 = 0.98^3 R^3 \] Thus, \[ V_f = \frac{4}{3} \pi (0.98^3 R^3) \] ### Step 5: Calculate the Change in Volume The change in volume \( \Delta V \) is given by: \[ \Delta V = V_i - V_f = \frac{4}{3} \pi R^3 - \frac{4}{3} \pi (0.98^3 R^3) \] Factoring out \( \frac{4}{3} \pi R^3 \): \[ \Delta V = \frac{4}{3} \pi R^3 \left(1 - 0.98^3\right) \] ### Step 6: Calculate the Volumetric Strain The volumetric strain \( \epsilon_v \) is defined as the change in volume divided by the initial volume: \[ \epsilon_v = \frac{\Delta V}{V_i} = \frac{\frac{4}{3} \pi R^3 \left(1 - 0.98^3\right)}{\frac{4}{3} \pi R^3} \] This simplifies to: \[ \epsilon_v = 1 - 0.98^3 \] ### Step 7: Calculate \( 0.98^3 \) Calculating \( 0.98^3 \): \[ 0.98^3 \approx 0.941192 \] So, \[ \epsilon_v = 1 - 0.941192 \approx 0.058808 \] ### Step 8: Express in Scientific Notation Converting \( 0.058808 \) into scientific notation gives: \[ \epsilon_v \approx 5.88 \times 10^{-2} \] ### Step 9: Round to Appropriate Significant Figures Rounding \( 5.88 \times 10^{-2} \) gives approximately \( 6 \times 10^{-2} \). Thus, the volumetric strain produced in the ball is: \[ \epsilon_v \approx 6 \times 10^{-2} \] ### Final Answer The volumetric strain produced in the ball is \( 6 \times 10^{-2} \). ---
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