The sides of rectangular plate of mass 20 kg is 5 m x 4 m placed on a horizontal table. The pressure exerted by the block on the table is (Take `g = 10 m/s^2`)

Options

A. 10 Pa
B. 100 Pa
C. 20 Pa
D. 30 Pa

Answer

To solve the problem of finding the pressure exerted by a rectangular plate on a horizontal table, we can follow these steps:

### Step 1: Identify the given values
- Mass of the rectangular plate (m) = 20 kg
- Dimensions of the plate = 5 m x 4 m
- Acceleration due to gravity (g) = 10 m/s²

### Step 2: Calculate the weight of the plate
The weight (force due to gravity) of the plate can be calculated using the formula:
\[ \text{Weight} (F) = m \times g \]
Substituting the values:
\[ F = 20 \, \text{kg} \times 10 \, \text{m/s}^2 = 200 \, \text{N} \]

### Step 3: Calculate the area of the plate
The area (A) of the rectangular plate can be calculated using the formula:
\[ A = \text{length} \times \text{width} \]
Substituting the dimensions:
\[ A = 5 \, \text{m} \times 4 \, \text{m} = 20 \, \text{m}^2 \]

### Step 4: Calculate the pressure exerted by the plate
Pressure (P) is defined as the force (F) applied per unit area (A):
\[ P = \frac{F}{A} \]
Substituting the values we calculated:
\[ P = \frac{200 \, \text{N}}{20 \, \text{m}^2} = 10 \, \text{Pa} \]

### Final Answer
The pressure exerted by the rectangular plate on the table is **10 Pa** (Pascals).

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