At `39.2°F` , specific volume and density of water are respectively

Options

A. Minimum and maximum
B. Minimum and minimum
C. Maximum and minimum
D. Maximum and maximum

Answer

To solve the problem regarding the specific volume and density of water at 39.2°F, we will follow these steps:

### Step 1: Convert Fahrenheit to Celsius
We will use the formula to convert Fahrenheit (F) to Celsius (C):

\[ T_C = \frac{5}{9} (T_F - 32) \]

Substituting \(T_F = 39.2°F\):

\[ T_C = \frac{5}{9} (39.2 - 32) \]
\[ T_C = \frac{5}{9} (7.2) \]
\[ T_C = 4°C \]

### Step 2: Analyze the properties of water at 4°C
At 4°C, water exhibits its anomalous properties. This means:

- The specific volume of water is at its minimum.
- The density of water is at its maximum.

### Step 3: State the specific volume and density
- The specific volume of water at 4°C is approximately \(0.00100 \, m^3/kg\).
- The density of water at 4°C is approximately \(1000 \, kg/m^3\).

### Conclusion
Thus, at 39.2°F (which is equivalent to 4°C), the specific volume and density of water are respectively:

- Specific Volume: \(0.00100 \, m^3/kg\)
- Density: \(1000 \, kg/m^3\)