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Just outside a sharp point on a conducto...

Just outside a sharp point on a conductor , we will have , a larger ______ than just outside gradually curving places on the conductor.

A

Electric field

B

Potential

C

Both (1) and (2)

D

None of these

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The correct Answer is:
To solve the question, we need to understand the relationship between the shape of a conductor and the electric field just outside its surface. ### Step-by-Step Solution: 1. **Understanding the Conductor's Shape:** - Consider a conductor with various shapes, specifically focusing on a sharp point and a gradually curving area. The sharp point is denoted as point P, and the gradually curving area is denoted as point Q. 2. **Electric Field and Potential:** - The electric potential (V) is the same across the surface of a conductor in electrostatic equilibrium. Thus, \( V_P = V_Q \) where \( V_P \) is the potential at point P and \( V_Q \) is the potential at point Q. 3. **Electric Field Relation:** - The electric field (E) just outside the surface of a conductor is related to the surface charge density (σ) and the radius of curvature (R) of the surface. The formula for the electric field near a charged conductor is given by: \[ E = \frac{\sigma}{\epsilon_0} \] - For a point charge, the electric field can also be expressed as: \[ E = \frac{KQ}{R^2} \] - Here, K is a constant, Q is the charge, and R is the radius of curvature. 4. **Comparing Electric Fields:** - At point P (the sharp point), the radius of curvature (R) is smaller than at point Q (the gradually curving area). Since the electric field is inversely proportional to the radius of curvature, we have: \[ E_P > E_Q \] - This means that the electric field just outside the sharp point (P) is larger than that just outside the gradually curving area (Q). 5. **Conclusion:** - Therefore, just outside a sharp point on a conductor, we will have a larger electric field than just outside gradually curving places on the conductor. ### Final Answer: Just outside a sharp point on a conductor, we will have a larger **electric field** than just outside gradually curving places on the conductor.
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