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sin alpha=sinbeta, cos alpha=cos beta th...

`sin alpha=sinbeta, cos alpha=cos beta` then

A

`sin((alpha+beta)/2=0`

B

`cos(((alpha+beta))/2)=0`

C

`sin(((alpha-beta))/2)=0`

D

`cos(((alpha-beta))/2)=0`

Text Solution

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The correct Answer is:
C
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