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If f and 'g' are differentiable functions in [0, 1] satisfying f(0) = 2 = g(1), g(0) = 0 and f(1) = 6, then for some c `in` [0,1]:

A

2f(c ) = g(c )

B

2f(c )=3g(c )

C

f(c )=g(c )

D

f(c ) =2g (C )

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The correct Answer is:
D
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