bar( r )xx bar(a)=bar(b)xx bar(a),bar( r...

`bar( r )xx bar(a)=bar(b)xx bar(a),bar( r )xx bar(b)=bar(a)xx bar(b),bar(a) ne bar(0),bar(b) ne bar(0)bar(a)ne lambda bar(b)`. If `bar(a).bar(b)=0` then `bar( r )` = ………….

A

`bar(a)-bar(b)`

B

`bar(a)+bar(b)`

C

`bar(a)xx bar(b)+bar(a)`

D

`bar(a)xx bar(b)+bar(b)`

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The correct Answer is:

B

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