In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. What is the percentage of sulphur in the compound ? (Ba = 136, S= 32, O= 16)

Explanation

molar mass of `BaSO_(4) = Ba + S + 4(O)`
`= 137 + 32 + 64`
= 233g
`underset(32g)(S ) overset(NHO_(3))rarr H_(2)SO_(4) overset(BaCl_(2))rarr underset(233g)(BaSO_(4))`
`:. 233g BaSO_(4)` contain 32g sulphur
0.4813g `BaSO_(4)` contain
mass of sulphur `= (32 xx 0.4813)/(233)gm`
%S `= (32)/(233) xx (0.4813)/(0.157) xx 100`
= 42.10%