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Find the direction cosines of the normal...

Find the direction cosines of the normal to the plane `x+2y+2z-4=0`

Text Solution

Verified by Experts

The correct Answer is:
`((1)/(3),(2)/(3),(2)/(3))`
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Lines bar(OA),bar(OB) are drawn from O with direction cosines proportional to (1,-2,-1), (3,-2,3). Find the direction cosines of the normal to the plane AOB.

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Knowledge Check

  • If A = (1, 8, 4) , B= (2, -3, 1) , then the direction cosines of a normal to the plane AOB is

    A
    A `2/sqrt(78) , 5 /sqrt(78), (-7)/sqrt(78)`
    B
    B `(2sqrt(10))/9, (7sqrt(10))/90, (-19sqrt(10))/90`
    C
    C `4/sqrt(218) , 9 /sqrt(218), (-11)/sqrt(218)`
    D
    D `2/11, 6/11, (-9)/11`
  • The direction cosines of the normal drawn to the plane passing through the points (2, -1, 5), (1, -3, 4), (5, 2, 1) are

    A
    `(11)/(sqrt(179)) , (-7)/(sqrt(179)), (3)/(sqrt(179))`
    B
    `(9)/(sqrt(134)), (-7)/(sqrt(134)), (2)/(sqrt(134))`
    C
    `(11)/(sqrt(179)) , (7)/(sqrt(179)), (-3)/(sqrt(179))`
    D
    `(9)/(sqrt(134)), (-7)/(sqrt(134)), (-2)/(sqrt(134))`
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