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If A+B+C=180^@ " then " sin 3A+ sin 3B+ ...

If `A+B+C=180^@ " then " sin 3A+ sin 3B+ sin 3C= `

A

`4"cos"(3A)/(2)"cos"(3B)/(2) "cos"(3C)/(2)`

B

`-4"cos"(3A)/(2)"cos"(3B)/(2) "cos"(3C)/(2)`

C

`1-4"cos"(3A)/(2)"cos"(3B)/(2) "cos"(3C)/(2)`

D

`1-4"sin"(3A)/(2)"sin"(3B)/(2) "sin"(3C)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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