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In DeltaABC, a=6,b=4 and cos (A-B)=4//5 ...

In `DeltaABC, a=6,b=4 and cos (A-B)=4//5` then its area is

A

`9//2`

B

3

C

6

D

9

Text Solution

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The correct Answer is:
D
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AAKASH SERIES-REVISION EXERCISE-PROPERTIES OF TRIANGLES
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