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If the area of the triangle ABC is a^(2)...

If the area of the triangle ABC is `a^(2)-(b-c)^(2)` then its circumradius R=

A

`((a)/(6))sin^(2)((A)/(2))`

B

`((a)/(16))"cosec"^(2)((A)/(2))`

C

`((b)/(16)) sin^(2)((B)/(2))`

D

`((c)/(16)) sin^(2)((C)/(2))`

Text Solution

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The correct Answer is:
B
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