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tan["cos"^(-1)4/5+"tan"^(-1)2/3]=...

`tan["cos"^(-1)4/5+"tan"^(-1)2/3]=`

A

`17/6`

B

`6/17`

C

`17/5`

D

`5/17`

Text Solution

Verified by Experts

The correct Answer is:
A
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