Calculate the EMF of the cell for the reaction
`Mg_((s))+2Ag_((aq))^(+)rarr Mg_((aq))^(2+)+2Ag_((s))`.
`("Given " :E^(@)Mg^(2+)//Mg=-2.37V, E^(@)Ag^(+)//Ag=0.80V, [Mg^(2+)]=0.001M[Ag^(+)]=0.001M and log10^(5)=5)`.

Explanation

`E_("cell")^(@)=E_("cathode")^(@)-E_("anode")^(@)`
`E_("cell")^(@)=E_(Ag^(+)//Ag)^(@)-E_(Mg^(2+)//Mg)^(@)`
`E_("cell")^(@)=0.80-(-2.37)`
`E_("cell")^(@)=3.17V`
`E_("cell")=E_("cell")^(@)-(0.059)/(n)log""([Mg^(2+)])/([Ag^(+)]^(2))`
`E_("cell")=3.17-(0.059)/(2)log""([0.001])/([0.0001]^(2))`
`E_("cell")=3.17-(0.059)/(2)log10^(5)`
`E_("cell")=3.17-(0.059)/(2)xx5`
`E_("cell")=3.022V`