Calcium metal crystallises in a face centered cubic lattice with edge length of 0.556nm. Calculate the density of the metal. [Atomic mass of calcium 40 g/mol]
`[N_(A) = 6.022 xx 10^(23) " atoms/ mol"]`

Explanation

Given : ` a = 0.556 nm = 0.556 xx 10^(-9) m = 5.56 xx 10^(-8) cm , Z =4 `. M = 40 g/mol
` d=(ZM)/(a^(3) N_(A)) = (4 xx 40)/( (5.56 xx 10^(-8)) xx 6.022 xx 10^(23)) = 1.54 g// cm^(3)`