A wire has a resistance of `2.5Omega` at `100^(@)C`. Temperature coefficient of resistance of the material `alpha=3.6xx10^(-3)K^(-1)`. Find its resistance at `0^(@)C`.

Explanation

`alpha=(R_(t)-R_(0))/(R_(0)(t_(2)-t_(1))),3.6xx10^(-3)=(2.5xxR_(0))/(R_(0)xx100)`
`R_(0)=(2.5)/(1.36),R_(0)=1.83Omega`