A rectangular block has dimensions 5 cm `xx ` 5 cm `xx 10 cm ` . Calculate the resistance measured between (a) two square ends and (b) the opposite rectanglar ends specific resistance of the material is `3.5xx10^(-5)` `Omega` m

Explanation

a) Resistance between two square ends
`R_(1)=(rhol)/(A)rArr R_(1)=(3.5xx10^(-5)xx10xx10^(-2))/(5xx5xx10^(-4))`
`=1.4xx10^(-3)Omega`

b) Resistance between the opposite rectangular ends
`R_(2)=(rhol)/(A)rArr R_(2)=(3.5xx10^(-5)xx5xx10^(-2))/(5xx10xx10^(-4))=3.5xx10^(-4)Omega`