Two wires of same material have their lengths in the ratio 2:3 and radii 8:9 . Equal value of p.d is applied between their ends (separately). Calculate the ratio of current through those two

Explanation

We know that `R=(rhol)/(A)=(rhol)/(pir^(2))`
`R=(V)/(I),(V)/(I)=(rhol)/(pir^(2))rArr I=(Vpir^(2))/(rhol)`
`I prop (r^(2))/(l),(I_(1))/(I_(2))=(r_(1)^(2))/(l_(1))xx(l_(2))/(r_(2)^(2))` `(I_(1))/(I_(2))=(r_(1)^(2))/(r_(2)^(2))xx((l_(2))/(l_(1)))=(8^(2)xx3)/(9^(2)xx2)=(64xx3)/(81xx2)=(32)/(27)rArr I_(1):I_(2)=32:27`