Two wires A and B of same mass and material are taken. Diameter of wire A is half of wire B. If resistance of wire A is `24Omega` find the resistance of wire B.

Explanation

`R=(rhom)/(A^(2)d),(R_(A))/(R_(B))=((r_(B))/(r_(A)))^(4)`
`rArr r_(A)=(r_(B))/(2)rArr (R_(A))/(R_(B))=(2)^(4)=16`
`therefore R_(B)=(R_(A))/(16)=(24)/(16)="1.5 ohm."`