What will be the resistance of a semi circle shown in fig., between its two end faces. Given that radial thickness is 3cm, axial thickness is 4 cm, inner radius is 6 cm and specific resistance is `4xx10^(-6)" ohm "-cm`

Explanation

`R=(rhol)/(A)=(rho pi((r_(1)+r_(2)))/(2))/(A)`
`R=(4xx10^(-6)(pi((6+9)/(2))))/(12)`
`R=(4xx10^(-6)(pi(7.5)))/(12)=7.85xx10^(-6)Omega`