Find potential difference between points A and B of the network shown in Fig. and distribution of given main current through different resistors.

Explanation

Between points A and B resistors of `4Omega, 6Omega and 8Omega` resistance are in series and these in parallel to `9Omega` resistor.
Equivalent resistance of series combination is
`R_(1)=(4+6+8)" ohm "=18`
If equivalent resistance between A and B is
`R=9xx18//(9+18)" ohm"=6Omega`
Potential difference between A and B is
`V=IR=2.7xx6V=16.2V`
Current through `9Omega` resistor `=16.2//9=1/8A`
Current through `4Omega, 6Omega and 8Omega` resistor `=2.7-1.8=0.9A`.