If two bulbs of 25 W and 100 W rated at 220 V are connected in series across 440 V supply. Will both the bulbs fuse? If not which one?

Explanation

For an e electrical appliance `R=((V_(s)^(2))/(W))`
`(R_(25))/(R_(100))=(W_(100))/(W_(25))=(100)/(25)=4" If "R_(100)-R, R_(25)=4R`
`"in series, "V_(25)=(VxxR_(25))/(R_(25)+R_(100))440xx(4)/(5)=352V`
`V_(100)=440-353=88V`
From this it is clear that voltage across 100 W bulb is lesser than specified (220 V). While across 25 W bulb is greater than (220V) so 25 W will fuse.
If the bulbs are connected in parallel to 440 V supply, both bulbs will be fused because, applied voltage across each bulb is 440 V greater than specified voltage (220V)