Two cells A and B each of 2V are connected in series to an external resistance R = 1 ohm. The internal resistance of A is `r_(A)=1.9` ohm and B is `r_(B)=00.9` ohm. Find the potential difference between the terminals of A.

Explanation

Total current through the circuit
`i=("voltage")/("Total resisance")`
`=(4)/((1+1.9+0.9))=(4)/(3.8)A`

potential difference at A,
`V_(A)=epsilon-ir =2-(4)/(3.8)xx1.9=2-2=0`.