In the given circuit as shown below, calculate the magnitude and direction of the current

Explanation

Effective resistance of the circuit is `R_("eff")=2+2+1=5Omega`
`therefore" total current in the circuit is I"=(V_(1)-V_(2))/(R_("eff"))`
`i=(10-5)/(5)=1A`
Since the cell of larger emf decides the direction of flow of current, the direction of current in the circuit is from A to B through e