A force vecF=(5hati+3hatj) Newton is app...

A force `vecF=(5hati+3hatj)` Newton is applied over a particle which displaces it from its origin to the point `vecr=(2hati-1hatj)` metres. The work done on the particle is

`– 7` joules

`+13` joules

`+7` joules

`+11` joules

Text Solution

Verified by Experts

The correct Answer is:

`W=vec(F).vec(s)=(5hat(i)+3hat(j)).(2hat(i)-hat(j))=10-3=7J`

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