A ball is released from the top of a tower. The ratio of work done by force of gravity in 1st second, 2nd second and 3rd second of the motion of ball is

Options

A. `1:2:3`
B. `1:4:9`
C. `1:3:5`
D. `1:5:3`

Answer

C

Explanation

When the ball is released from the top of tower then ratio of distances covered by the ball in first, second and third second
`h_(I):h_(II):h_(III)=1:3:5: " " ["because " h_(n)prop(2n-1)]`
`therefore` Ratio of work done `mgh_(I):mgh_(II):mgh_(III)=1:3:5`