Two springs of spring constants `1500N//m` and `3000N//m` respectively are streched by the same force. The potential energy gained by the two springs will be in the ratio

Options

A. `4:1`
B. `1:4`
C. `2:1`
D. `1:2`

Answer

C

Explanation

`U=(F^(2))/(2k)rArr (U_(1))/(U_(2))=(k_(2))/(k_(2)) " "` (if force are same)
`therefore (U_(1))/(U_(2))=(3000)/(1500)=(2)/(1)`