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A position dependent force F=7-2x+3x^(2)...

A position dependent force `F=7-2x+3x^(2)` acts on a small body of mass 2 kg and displaced it from `x=0` to `x=5m`. Calculate the work done in joule.

A

70

B

270

C

35

D

135

Text Solution

Verified by Experts

The correct Answer is:
D
`W=int_(0)^(5)Fdx = int_(0)^(5)(7-2x+3x^(2))dx=[7x-x^(2)+x^(3)]_(0)^(5)`
`= 35-25+125=135 J`
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