The force constant of a wire is k and that of another wire is . 2k When both the wires are stretched through same distance, then the work done

Options

A. `W_(2)=2W_(1)^(2)`
B. `W_(2)=2W_(1)`
C. `W_(2)=W_(1)`
D. `W_(2)=0.5W_(1)`

Answer

B

Explanation

`W=(1)/(2)kx^(2)`
If both wires are stretched through same distance then
`W prop k`. As `K_(2)=2k_(1)` so `W_(2)=2W_(1)`