A body of mass m accelerates uniformly from rest to `v_1` in time `v_2`. As a function of time t, the instantaneous power delivered to the body is

Options

A. `(mv_(1)t)/(t_(1))`
B. `(mv_(1)^(2)t)/(t_(1)`
C. `(mv_(1)t^(2))/(t_(1))`
D. `(mv_(1)^(2)t)/(t_(1)^(2))`

Answer

D

Explanation

`P= vec(F).vec(v) = ma xx a t = ma^(2)t` [as u= o]
`=m ((v_(1))/(t_(1)))^(2) t= (mv_(1)^(2) t)/(t_(1)^(2))` [As `a= v_(1)//t_(1)`]