A car of mass 1250 kg is moving at `30(m)//(s)`. Its engine delivers 30 kW while resistive force due to surface is 750 N. What maximum acceleration can be given to the car

Options

A. `(1)/(3)m//s^(2)`
B. `(1)/(4)m//s^(2)`
C. `(1)/(5)m//s^(2)`
D. `(1)/(6)m//s^(2)`

Answer

C

Explanation

Force produced by the engine `F= (P)/(v) = (30 xx 10^(3))/(30)= 10N`
Acceleration `= ("Forward force by engine- resistive force")/("mass of car")`
`=(1000-750)/(1250)= (250)/(1250)= (1)/(5) m//s^(2)`