A force applied by an engine of a train of mass `2.05xx10^6`kg changes its velocity from 5 m/s to 25 m/s in 5 minutes. The power of the engine is

Options

A. 1.025 MW
B. 2.05 MW
C. 5 MW
D. 6 MW

Answer

B

Explanation

Power `= ("Work done")/("time") = ((1)/(2) m(v^(2)-u^(2)))/(t)`
`F= (1)/(2) xx (2.05 xx 10^(6) xx [(25)^(2)-(5^(2))])/(5 xx 60)`
`P= 2.05 xx 10^(6)W= 2.05 MW`