An engine pumps up `100 kg` water through a height of `10 m` in `5 s`. If efficiency of the engine is `60%`. What is the power of the engine? `Take g = 10 ms^(2)`.

Options

A. 3.3 kW
B. 0.33 kW
C. 0.033 kW
D. 33 kW

Answer

A

Explanation

Work output of engine `=mgh= 100 xx 10 xx 10= 10^(4)J`
Efficiency `(eta)= ("output")/("input") therefore` Input energy `= ("outupt")/(eta)`
`=(10^(4))/(60) xx 100 = (10^(5))/(6)J`
`therefore` Power `= ("input energy")/("time")= (10^(5)//6)/(5)= (10^(5))/(30)= 3.3 kW`