A man does a given amount of work in 10 sec. Another man does the same amount of work in 20 sec. The ratio of the output power of first man to the second man is

Options

A. 1
B. 1//2
C. 2//1
D. None of these

Answer

C

Explanation

Power `=(W)/(t)`. If W is constant then `P prop (1)/(t)`
i.e., `(P_(1))/(P_(2)) = (t_(2))/(t_(1))= (20)/(10)= (2)/(1)`